a) Gọi số cần tìm là: `x`   \(\left(x\in Q;x\ne0\right)\)

Ta có: \(-\dfrac{25}{16}=\dfrac{-5}{12}x\)

`=>` \(x=-\dfrac{25}{16}\div\dfrac{-5}{12}=\dfrac{15}{4}\)

Vậy \(-\dfrac{25}{16}=\dfrac{15}{4}.\dfrac{-5}{12}\).

b) Gọi số cần tìm là: \(y\)   \(\left(y\in Q;y\ne0\right)\)

Ta có: \(-\dfrac{25}{16}=-\dfrac{4}{5}\div y\)

\(\Rightarrow y=-\dfrac{4}{5}\div\dfrac{-25}{16}=\dfrac{64}{125}\)

Vậy \(-\dfrac{25}{16}=-\dfrac{4}{5}\div\dfrac{64}{125}\).

a) Gọi số cần tìm là: x=−2516÷−512=154

Vậy 

−2516=−45÷64125

.

\(a)\)

\(\frac{-25}{16}=\frac{\left(-5\right).5}{4.4}=\frac{\left(-5\right).5.3}{4.4.3}=\frac{\left(-5\right).15}{12.4}=\frac{\left(-5\right)}{12}.\frac{15}{4}\)

\(b)\)

\(\frac{-25}{16}=\frac{\left(-25\right).4.5}{16.4.5}=\frac{\left(-4\right).25.5}{5.16.4}=\frac{\left(-4\right)}{5}.\frac{125}{64}=\frac{\left(-4\right)}{5}:\frac{64}{125}\)

                                                             Giải

a) Ta có : \(\frac{-25}{16}=\frac{-5}{12}.\frac{15}{4}\)

b) Ta có : \(\frac{-25}{16}=\frac{-4}{5}.\frac{64}{125}\)

\(a,\dfrac{-3}{35}=\dfrac{-5}{7}\cdot\dfrac{3}{25}\\ b,\dfrac{-3}{35}=\dfrac{-2}{5}:\dfrac{14}{3}\)

a: \(\dfrac{-3}{35}=\dfrac{-5}{7}\cdot\dfrac{3}{25}\)

b: \(-\dfrac{3}{35}=\dfrac{-2}{5}:\dfrac{14}{3}\)

a: −335=−25:143

Mỗi câu có nhiều đáp án, chẳng hạn:

a) =

b)

Lời giải:

Mỗi câu có nhiều đáp án, chẳng hạn:

a) =

b)

\(a...\dfrac{-5}{16}=\dfrac{-5}{4}\cdot\dfrac{1}{4}=\dfrac{-5}{8}\cdot\dfrac{1}{2}=\dfrac{-10}{2}\cdot\dfrac{1}{16}=......\)

\(b...\dfrac{-5}{16}=\dfrac{-5}{8}:2=\dfrac{-5}{4}:4=.....\)

a) \(\dfrac{-7}{20}=\dfrac{1}{5}.\dfrac{-7}{4}\) b) \(\dfrac{-7}{20}=\dfrac{-7}{40}:\dfrac{1}{2}\) c) \(\dfrac{-7}{20}=\dfrac{2}{5}+\dfrac{-3}{4}\) d) \(\dfrac{-7}{20}=\dfrac{-1}{5}+\dfrac{-3}{20}\)

a)\(\dfrac{-7}{20}=\dfrac{-7}{10}\times\dfrac{1}{2}\)

b)\(\dfrac{-7}{20}=\dfrac{-7}{40}\times\dfrac{1}{2}\)

c)\(\dfrac{-7}{20}=\dfrac{7}{20}+\dfrac{-7}{10}\)

d)\(\dfrac{-7}{20}=\dfrac{-1}{5}+\dfrac{-3}{20}\)

a: \(\dfrac{-11}{81}=\dfrac{1}{27}\cdot\dfrac{-11}{3}\)

b: \(\dfrac{-11}{81}=\dfrac{1}{27}:\dfrac{3}{-11}\)

A. 16/35 x -7/10= -8/25

B.12/5 : -15/2 = -8/25

a: \(-\dfrac{8}{25}=\dfrac{-7}{10}\cdot\dfrac{16}{35}\)

b: \(-\dfrac{8}{25}=\dfrac{12}{5}:\dfrac{-15}{2}\)